how do i solve these equations..
1. A Cyanide Solution with a 12.73 ml was treated with 25.00 ml of Ni^2+ solution containing (excess Ni^2+) to convert cyanide into tetracyanonickelate (II)
4CN + Ni2+ ----> Ni(CN)4
the excess Ni2+ was then titrated with 10.15 ml of 0.01307 M EDTA
Ni2+ + EDTA ----> Ni(EDTA)2-
Ni(CN)3/4 does not react with EDTA. if 39.35 ml of EDTA were required to react with 30.10 ml of original Ni2+ solution, calculate the molarity of CN- in the 12.73 ml cyanide sample
2. a 50.0 ml aliquot solution containing 0.450g of MgS04 (FM 120.37) in 0.5L required 37.6 ml of EDTA solution for titration. How many milligrams of CaC03 (FM 100.09) will react with 1.00ml of this EDTA solution
1. A Cyanide Solution with a 12.73 ml was treated with 25.00 ml of Ni^2+ solution containing (excess Ni^2+) to convert cyanide into tetracyanonickelate (II)
4CN + Ni2+ ----> Ni(CN)4
the excess Ni2+ was then titrated with 10.15 ml of 0.01307 M EDTA
Ni2+ + EDTA ----> Ni(EDTA)2-
Ni(CN)3/4 does not react with EDTA. if 39.35 ml of EDTA were required to react with 30.10 ml of original Ni2+ solution, calculate the molarity of CN- in the 12.73 ml cyanide sample
2. a 50.0 ml aliquot solution containing 0.450g of MgS04 (FM 120.37) in 0.5L required 37.6 ml of EDTA solution for titration. How many milligrams of CaC03 (FM 100.09) will react with 1.00ml of this EDTA solution