Double Angle identities?

Aly Ren

New member
how to solve

cos(2a) - cos(4a) =0
cos2a - cos4a=0
cos2a - 2 cos^2(2a)-1 =0
set cos2a = y
y - 2y^2 -1 = 0
change sign
2y^2 - y + 1 =0
is this factor-able? stuck on this step!
 
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