A Aneseluv Guest Oct 20, 2009 #1 1) {a (sub n)} = (n+1) / (2n-3) n=1,2,3,.... 2) {a (sub n)} = [(n^2 - n)/(n^2 + n)]^ 1/2 n=1,2,3,....
1) {a (sub n)} = (n+1) / (2n-3) n=1,2,3,.... 2) {a (sub n)} = [(n^2 - n)/(n^2 + n)]^ 1/2 n=1,2,3,....