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Chemistry question dealing with concentration and pH please help?
1. The concentration of H3O+ ions in a solution is 3.8 x 10^-9 M
Is this solution acidic basic or neutral?
What is the concentration of OH- ions in this solution?
2. The concentration of OH- ions in a solution is 1.6 x 10^-6 M
Is this solution acidic basic or neutral?
What is the concentration of H3O+ ions in the solution?
3. In a solution, [OH- ] = 3.4 x 10^-10 M. What is the pH of the solution? Is it acidic or basic?
please show work since I dont understand how to do this. Thank you
1. pH = -lg(3.8 * 10^-9) = 8.42 since pH > 7, hence the solution is basic
pOH = 14.0 - pH = 5.58
5.58 = -lg(conc. OH- ions)
conc. OH- ions = 10^(-5.58) = 2.63 * 10^-6
2. pOH = -lg(1.6*10^-6) = 5.80
pH = 14.0 - pOH = 8.20 since pH > 7, solution is basic
pH = -lg(conc. H3O+ ions)
conc. H3o+ ions = 10^(-8.2) = 6.31 * 10^-9
3. pOH = -lg(3.4*10^-10) = 9.47
pH = 14.0 - 9.47 = 4.5
since pH < 7, hence the solution is acidic
cheers
1. pH = -lg(3.8 * 10^-9) = 8.42 since pH > 7, hence the solution is basic
pOH = 14.0 - pH = 5.58
5.58 = -lg(conc. OH- ions)
conc. OH- ions = 10^(-5.58) = 2.63 * 10^-6
2. pOH = -lg(1.6*10^-6) = 5.80
pH = 14.0 - pOH = 8.20 since pH > 7, solution is basic
pH = -lg(conc. H3O+ ions)
conc. H3o+ ions = 10^(-8.2) = 6.31 * 10^-9
3. pOH = -lg(3.4*10^-10) = 9.47
pH = 14.0 - 9.47 = 4.5
since pH < 7, hence the solution is acidic
cheers
1) basic
2.63 x10^-6 M
2) basic
6.25 x 10^-9 M
3) acidic
pH=4.53
1) basic
2.63 x10^-6 M
2) basic
6.25 x 10^-9 M
3) acidic
pH=4.53
I suggest you go to chemstryisrightforme.org. I luv using it and hopefully it would help you.
1) basic
2.63 x10^-6 M
2) basic
6.25 x 10^-9 M
3) acidic
pH=4.53
I suggest you go to chemstryisrightforme.org. I luv using it and hopefully it would help you.
1) basic
2.63 x10^-6 M
2) basic
6.25 x 10^-9 M
3) acidic
pH=4.53
1. pH = -lg(3.8 * 10^-9) = 8.42 since pH > 7, hence the solution is basic
pOH = 14.0 - pH = 5.58
5.58 = -lg(conc. OH- ions)
conc. OH- ions = 10^(-5.58) = 2.63 * 10^-6
2. pOH = -lg(1.6*10^-6) = 5.80
pH = 14.0 - pOH = 8.20 since pH > 7, solution is basic
pH = -lg(conc. H3O+ ions)
conc. H3o+ ions = 10^(-8.2) = 6.31 * 10^-9
3. pOH = -lg(3.4*10^-10) = 9.47
pH = 14.0 - 9.47 = 4.5
since pH < 7, hence the solution is acidic
cheers
1. pH = -lg(3.8 * 10^-9) = 8.42 since pH > 7, hence the solution is basic
pOH = 14.0 - pH = 5.58
5.58 = -lg(conc. OH- ions)
conc. OH- ions = 10^(-5.58) = 2.63 * 10^-6
2. pOH = -lg(1.6*10^-6) = 5.80
pH = 14.0 - pOH = 8.20 since pH > 7, solution is basic
pH = -lg(conc. H3O+ ions)
conc. H3o+ ions = 10^(-8.2) = 6.31 * 10^-9
3. pOH = -lg(3.4*10^-10) = 9.47
pH = 14.0 - 9.47 = 4.5
since pH < 7, hence the solution is acidic
cheers
