If 10.0 g of benzene reacts with an excess of water in a 5.0 L vessel at a temperature of 500 K, then what will be the increase in pressure due to the formation of H2? Assume that the volume of the liquid reactants is negligible.
C6¬H6(ℓ) + H2O(ℓ) -> C6H6O(s) + H2(g)
I know the answer i just need to know the steps to get there.
C6¬H6(ℓ) + H2O(ℓ) -> C6H6O(s) + H2(g)
I know the answer i just need to know the steps to get there.