Joel James
New member
Fill in the blanks:
_____g of KIO3 are needed to make 500 mL of a 18 M KIO3 solution
Thanks
_____g of KIO3 are needed to make 500 mL of a 18 M KIO3 solution
Thanks
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Chemistry please help?
- Thread starter Joel James
- Start date
molarity is moles of solute divided by liters of solution.
So, if you want only 500 mL of that solution, then you are going to need 9 moles of the KlO3. (half of a liter is 500 mL)
Okay, so now you want to set it up as such: (gfm is 214g/mole)
9 moles KlO3 (214g/1mole)
the moles cancel out of the equation
and your answer should be 1926 grams of KIO3 are needed.
So, if you want only 500 mL of that solution, then you are going to need 9 moles of the KlO3. (half of a liter is 500 mL)
Okay, so now you want to set it up as such: (gfm is 214g/mole)
9 moles KlO3 (214g/1mole)
the moles cancel out of the equation
and your answer should be 1926 grams of KIO3 are needed.
L
La La La La La
Guest
Why are you worried about chemistry in the summer?
t[H]e tig[E]r feve[R]
New member
I am not doing your homework unless I get paid..I'm no rocket scientist ya know.