xXWraithXx
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When copper(II) sulfate pentahydrate(blue crystals) is heated in air above 100 degree celcious, it loses the water molecule and also its blue colour
CuSO4 . 5H2O -> CuSO4 + 5H2O (there is a dot in between the reactant cuso4 and 5h2o)
If 9.6g of CuSO4 are left after heating above 100 degree celcius, 15.01g of the blue compound, calculate the number of moles of H20 originally present in the compound.
Please show me some guide in solving this problem
CuSO4 . 5H2O -> CuSO4 + 5H2O (there is a dot in between the reactant cuso4 and 5h2o)
If 9.6g of CuSO4 are left after heating above 100 degree celcius, 15.01g of the blue compound, calculate the number of moles of H20 originally present in the compound.
Please show me some guide in solving this problem