Chemistry help. thanks.?

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Schrodinger

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First we need to determine whether H2 or N2 is the limiting reagent:
1.16gH2 * (1molH2/2.016gH2) * (2molNH3/3molH2) * (17.031gNH3/1molNH3) = 6.53g NH3

10.4gN2 * (1molN2/28.0314gN2) * (2molNH3/1molN2) * (17.031gNH3/1molNH3) = 12.64g NH3

So H2 is the limiting reagent, and thus the maximum amount of NH3 that can be produced is 6.53g (theoretical yield)

Percent yield = (actual yield/theretical yield) * 100% = (1.48g/6.53g)*100% = 22.7%yield
 
3H2(g) + N2(g) --> 2NH3(g)
1.16g H2 is allowed to react with 10.4g N2, producing 1.48g NH3
1. What is the theoretical yield for this reaction under the given conditions? (in grams)
2. What is the percent yield for this reaction under the given conditions?
 
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