Find the enthalpy change for the following reaction using a) the enthalpy change of formation values and b) the enthalpy change of combustion values. Then comment on your two answers.
CH3(l) + H2(g) --> CH3CH2OH (l)
The standard enthalpy changes are
formation CH3CHO: -192 kj per mol
formation H2: 0 kj per mol
formation CH3CH2OH: -277 kj per mol
combustion CH3CHO: -1167 kj per mol
combustion H2: -286 kj per mol
combustion CH3CH2OH: -1367 kj per mol
I drew the triangle energy cycle thingy, and my answers are
a) -85 kj per mol
b) -86 kj per mol
Can you please tell me if these answers are correct, and if they are, how do I comment on them? I dont really know what to say except that the numbers are almost the same lol.
Thank you!
CH3(l) + H2(g) --> CH3CH2OH (l)
The standard enthalpy changes are
formation CH3CHO: -192 kj per mol
formation H2: 0 kj per mol
formation CH3CH2OH: -277 kj per mol
combustion CH3CHO: -1167 kj per mol
combustion H2: -286 kj per mol
combustion CH3CH2OH: -1367 kj per mol
I drew the triangle energy cycle thingy, and my answers are
a) -85 kj per mol
b) -86 kj per mol
Can you please tell me if these answers are correct, and if they are, how do I comment on them? I dont really know what to say except that the numbers are almost the same lol.
Thank you!