C Chad New member Jul 26, 2009 #1 What is the pG of the solution obrained by mixing 50.00mL of 0.250 M HCl and 50.00 mL of 0.500 M NaOH?
What is the pG of the solution obrained by mixing 50.00mL of 0.250 M HCl and 50.00 mL of 0.500 M NaOH?
D DocBubbles New member Jul 26, 2009 #2 .250 * 50 /100 = 0.125 M NaOH and you neutralize half of that = 0.0625M OH- Since in water [H]{OH] =1x10^-14 [H][0.0625]=1x10^-14 [H] = 16x10^-14 pH = -log(16x10^-14) = 0.903x10^-14 = 12.80
.250 * 50 /100 = 0.125 M NaOH and you neutralize half of that = 0.0625M OH- Since in water [H]{OH] =1x10^-14 [H][0.0625]=1x10^-14 [H] = 16x10^-14 pH = -log(16x10^-14) = 0.903x10^-14 = 12.80
