H Hiroji New member Sep 2, 2009 #1 During a particular observation, the Chandra telescope detects photons with an average energy of 2.0keV at a rate of 5×10−3 per second. What is the total power received, in watts? P=??????? w
During a particular observation, the Chandra telescope detects photons with an average energy of 2.0keV at a rate of 5×10−3 per second. What is the total power received, in watts? P=??????? w
A AALUNGA New member Sep 2, 2009 #2 Well!! 1 electron volt = 1.6E-19 joules Hence, Total Energy = 2 x E3 x 1.6 E-19 = 3.2 E-16 J Now, if comes to power, you receive 5 E-3 eV /s = 5E-3 x 1.6 E -19 = 8 E -22 W
Well!! 1 electron volt = 1.6E-19 joules Hence, Total Energy = 2 x E3 x 1.6 E-19 = 3.2 E-16 J Now, if comes to power, you receive 5 E-3 eV /s = 5E-3 x 1.6 E -19 = 8 E -22 W
A AALUNGA New member Sep 2, 2009 #3 Well!! 1 electron volt = 1.6E-19 joules Hence, Total Energy = 2 x E3 x 1.6 E-19 = 3.2 E-16 J Now, if comes to power, you receive 5 E-3 eV /s = 5E-3 x 1.6 E -19 = 8 E -22 W
Well!! 1 electron volt = 1.6E-19 joules Hence, Total Energy = 2 x E3 x 1.6 E-19 = 3.2 E-16 J Now, if comes to power, you receive 5 E-3 eV /s = 5E-3 x 1.6 E -19 = 8 E -22 W
