Can someone help me with log laws?

N

ness17

New member
We're starting to learn about logarithms at school and our teacher introduced us to the log laws. I understand them but was wondering how the following log laws work/can be proved. I asked my teacher but she wasn't sure and I was wondering if someone knew how the following can equate.

ylogax = logax^y
a^logam = m
logab = (logcb)/(logca) --> (change of base)

sorry, can't do subscript for the bases and superscript for powers, hopefully it's understandable though
 
ooooh dude.....can't you just accept them for what they are and not need a proof?? lol

the proofs are long calculations.....look it up on google
 
1)let ylogax=t. or,logax=t/y or,x=a^(t/y) [By def of log] or,x^y=a^t
or,logax^y=t.
so ylogax=logax^y [PROVED]
3)let logcb=x & logca=y.
so b=c^x & a=c^y. or,b^y=(c^x)^y=c^(xy)=(c^y)^x=a^x or,a^x=b^y
or,b=a^(x/y) or,logab=(logcb)/(logca) [PROVED]
hope it helps.
 
1) It is rather straight. ylogax is always derived from logax^y because it is the identity of log. You can check from the calculator. 3log4 is always equal to log4^3
 
1) It is rather straight. ylogax is always derived from logax^y because it is the identity of log. You can check from the calculator. 3log4 is always equal to log4^3
 
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