Can anyone please help me with this chemistry problem?

X

x_ultima_oblivion_x

New member
Calculate the volume (in L) of ethylene glycol in a radiator that contains 2390 g ethylene glycol. The density of ethylene glycol is 1.11g/mL)

Also, please explain how to do the problem.
Thank you !
 
density = mass/volume, density and mass of the ethylene glycol are given so it is volume=m/p =2153.15mL=2.153L
 
Easy look at that:

2390/1,11 = numbers of ml = 2 153,15315
Numbers of L = ml/1000 = 2153,15315/1000

There is 2,15315315 L of Ethylene glycol in the radiator.
 
Back
Top