Can anybody solve this riddle?

  • Thread starter Thread starter Kelly Laine
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Kelly Laine

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The following riddle is on the Professer Layton DS game & I can't solve it. This is exactly what is says on the screen (even the hints.)
Here it is...
"While walking through a market on vacation, you notice a small stand selling cameras. A camera & case set is selling for $310. The seller tells you that the camera costs $300 more than the case itself and the case costs the price of the set minus the cost of the camera.
You decide you'd rather wait on buying a camera & opt to just buying the case alone. You hand the seller a $100 bill and see his eyes light up. Think fast now!
How much change should you be getting back?"

I have tried 90,89,80, & 70.
I have unlocked the following hints...
1.The puzzle isn't math intensive, but there is a particularly tricky aspect to it that trips most people up.
The camera and case cost a total of $310. but differ in price by $300.
2.Ok, if you assume the case costs X, then the camera must cost X plus $300
This means the camera itself must cost more than $300.
3.The case and camera cost $310 together. The camera costs $300 more than the case.
It may seem like the answer is $300 for the camera and $10 for the case, but if you do the math, you'll see that the difference in price is only$290.
Have you noticed that already.
 
let x = cost of cam, let y = cost of case

x + y = 310
x = 300 + y
y = 310 - x

Replace the y in the second equation with (310 - x) to get:
x = 300 + 310 - x
x = 610 - x
2x = 610
x = 305
so the camera costs $305. And 310 - 305 = 5, so the case is $5.

100 - 5 = $95 in change.
 
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