calculus - find the equation of the normal to:?

Mopz

New member
um yea, been trying to this problem for ages, cant seem to get the right answer. heres the question

find the equation of the normal to f(x = ( x^2 - ) / 2x + 3 at the point where x = - 1

so i use quotient rule right? according to my answer my normal ends up being 1/2 - which is probably wrong.

then yea... i do like 1/2 = y + 2 / x + 1

and get like 2y = x + 3, but this is not correct.

it should be 2Y = x + 1,


Yea working to this question woud be great, thanks
 
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