calculate the pressure and force on an inspection hatch 0.75m diameter located on the bottom of a tank when it is filled with oil of density 875 kg/m³ to a depth of 7m.
If only the weight of the hatch is applied
Then the force acting is the weight of the tank = mg = (Density)*(Volume)*g
V = (pi/4)*((0.75)^2)*7
Density = 875
Then F = 26545.3 N
Pressure = Force/Area
Area = (pi/4)*((0.75)^2)
Then P = 60086.25 Pa
