Calculate the potential of the following cell? Cu(s)/Cu(NO3)2 (0.02M)//Fe(NO3)2...

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...(0.05M)/Fe(s)? Calculate the potential of the following cell?
And determine whether the reaction is spontaneous (is the cell potential >0)

(Fe2+) + (2e-) -> Fe(s) E= -0.44v
(Cu2+) + (2e-) -> Cu(s) E= 0.339 V

Cu(s)/Cu(NO3)2 (0.02M)//Fe(NO3)2 (0.05M)/Fe(s)
 
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