Calculate the capacitance of this system of ornaments?

R

Reyco

New member
For letter A:

Capacitance = Charge / Voltage
Capacitance = (50 x 10^-6) / 10
Capacitance = 5x10^-6 Farad
Capacitance = 5 uF <---answer in microfarad

------------------------------------------------------------
For letter B:

The capacitance wouldn't change even though the charge between the ornaments changed. The capacitance is only dependent with the area of the metal, distance between metals and the property of the dielectric material / vacuum / air.

------------------------------------------------------------
For letter C:

if the change changed to +200uC and -200uC

Voltage = Charge / Capacitance
Voltage = (200 x 10^-6) / (5x10^-6)
Voltage = 40 volts <---answer
 
Two metal ornaments have net charges of +50uC and -50uC, and this creates a 10 volt electric potential difference between the ornaments.
A) Calculate the capacitance of this system of ornaments.
B) If the net charges are changed to +200uC and -200uC what would happen to the capacitance of the system?
C) What would become of the electric potential difference between the two metal ornaments?
 
For letter A:

Capacitance = Charge / Voltage
Capacitance = (50 x 10^-6) / 10
Capacitance = 5x10^-6 Farad
Capacitance = 5 uF <---answer in microfarad

------------------------------------------------------------
For letter B:

The capacitance wouldn't change even though the charge between the ornaments changed. The capacitance is only dependent with the area of the metal, distance between metals and the property of the dielectric material / vacuum / air.

------------------------------------------------------------
For letter C:

if the change changed to +200uC and -200uC

Voltage = Charge / Capacitance
Voltage = (200 x 10^-6) / (5x10^-6)
Voltage = 40 volts <---answer
 
For letter A:

Capacitance = Charge / Voltage
Capacitance = (50 x 10^-6) / 10
Capacitance = 5x10^-6 Farad
Capacitance = 5 uF <---answer in microfarad

------------------------------------------------------------
For letter B:

The capacitance wouldn't change even though the charge between the ornaments changed. The capacitance is only dependent with the area of the metal, distance between metals and the property of the dielectric material / vacuum / air.

------------------------------------------------------------
For letter C:

if the change changed to +200uC and -200uC

Voltage = Charge / Capacitance
Voltage = (200 x 10^-6) / (5x10^-6)
Voltage = 40 volts <---answer
 
For letter A:

Capacitance = Charge / Voltage
Capacitance = (50 x 10^-6) / 10
Capacitance = 5x10^-6 Farad
Capacitance = 5 uF <---answer in microfarad

------------------------------------------------------------
For letter B:

The capacitance wouldn't change even though the charge between the ornaments changed. The capacitance is only dependent with the area of the metal, distance between metals and the property of the dielectric material / vacuum / air.

------------------------------------------------------------
For letter C:

if the change changed to +200uC and -200uC

Voltage = Charge / Capacitance
Voltage = (200 x 10^-6) / (5x10^-6)
Voltage = 40 volts <---answer
 
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