bullet newtons law ?

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llamaman

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Use the equation V^2=Vo^2+2a(X-Xo) to solve for the acceleration.

Then you can say that F=ma (m=mass of the bullet)

This statement is in agreement with newtons Second law of motion
 
A bullet of mass 0.002 kg initially moving at 487 m/s embeds itself in a large fixed piece of wood and travels 0.55 m before coming to rest. Assume that the acceleration of the bullet is constant.

What force is exerted by the wood on the bullet?
 
Use the equation V^2=Vo^2+2a(X-Xo) to solve for the acceleration.

Then you can say that F=ma (m=mass of the bullet)

This statement is in agreement with newtons Second law of motion
 
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