T t_o_p12 Guest Mar 25, 2009 #1 A bicycle has wheels with a diameter of 0.560 m. It accelerates uniformly and the rate of rotation of its wheels increases from 181 rpm to 290 rpm in a time of 27.7 s. Find the linear acceleration of the bicycle.
A bicycle has wheels with a diameter of 0.560 m. It accelerates uniformly and the rate of rotation of its wheels increases from 181 rpm to 290 rpm in a time of 27.7 s. Find the linear acceleration of the bicycle.
D David C Guest Mar 25, 2009 #2 firstly find the circumference of the wheel, π x D = 3.142 x 0.56 = 1.759 m 181 / 60 is rotations per second = 3.0167 3.0167 x 1.759 = starting velocity = 5.31 m /s 290 / 60 = 4.83 4.83 x 1.759 = final velocity = 8.5 m/s final - starting = 3.19 ~ 3.2 3.2 / 27.7 = acceleration = 0.1155 m / s^2
firstly find the circumference of the wheel, π x D = 3.142 x 0.56 = 1.759 m 181 / 60 is rotations per second = 3.0167 3.0167 x 1.759 = starting velocity = 5.31 m /s 290 / 60 = 4.83 4.83 x 1.759 = final velocity = 8.5 m/s final - starting = 3.19 ~ 3.2 3.2 / 27.7 = acceleration = 0.1155 m / s^2
