Another Question to Ask in Physics: Decibels?

T

thatdude112

New member
The equation β = (10 dB) log (I/I0), which defines the decibel, is sometimes written in terms of power P (in watts) rather than intensity I (in watts/m2). The form β = (10 dB) log (P/P0) can be used to compare two power levels in terms of decibels. Suppose that stereo amplifier A is rated at P = 254 watts per channel, while amplifier B has a rating of P0 = 45.9 watts per channel. Expressed in decibels, how much more powerful is A compared to B?

How can i compare the two? We definitly did not learn this? Could someone please show me steps and how you got this, I wish i knew were to begin. Any Help Would Be Appreciated!
 
Just use the given formula:
β = (10 dB)*log(P/P0)

and input the data for each amplifier.

It doesn't matter whether you've learned it or not, you are learning it now.

BE SURE that you are using base 10 logarithm on your calculator. If you only have ln, natural log, use the following:

β = (10 dB)*LN(P/P0)/LN(10)

Result:
β = 7.43 decibels
 
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