An object is placed in front of a convex mirror, and the size of the image is

G

gp4rts

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o = object distanc
i = image distance
magnification m = i/o
for m = 1/4 o = 4*i i = o/4

also

1/o + 1/i = 1/f

1/o + 4/o = 1/f

5/o = f o/5 =f

o/f = 5
 
one-fourth that of the object.? What is the ratio of the object distance to the focal length of the mirror?

Please include any calculations and explanations.
Thank you.
The answer is not 5 :(
 
o = object distanc
i = image distance
magnification m = i/o
for m = 1/4 o = 4*i i = o/4

also

1/o + 1/i = 1/f

1/o + 4/o = 1/f

5/o = f o/5 =f

o/f = 5
 
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