T Taylor New member May 26, 2010 #1 the problem is: 3h^2/2t^2-8 + h/t-2 I am lost on how to do this question and any help is greatly appreciated. Thanks!
the problem is: 3h^2/2t^2-8 + h/t-2 I am lost on how to do this question and any help is greatly appreciated. Thanks!
T TychaBrahe New member May 26, 2010 #2 You need to find a common denominator. 2t^2 - 8 = 2(t^2 - 4) = 2(t - 2)(t + 2) So 3h^2 / (2(t - 2)(t + 2)) + h(2(t - 2)/ (2(t - 2)(t + 2)) (3h^2 + 2ht - 4h)/(2t^2 - 8)
You need to find a common denominator. 2t^2 - 8 = 2(t^2 - 4) = 2(t - 2)(t + 2) So 3h^2 / (2(t - 2)(t + 2)) + h(2(t - 2)/ (2(t - 2)(t + 2)) (3h^2 + 2ht - 4h)/(2t^2 - 8)
