A torque of 0.92 N*m is applied to a bicycle wheel with a radius of 35cm and

[Bob G]

a mass of 0.90kg.? Treating the wheel as a hoop, what is its angular acceleration?

 

[(..._.) (.....)]

oops... got it wrong i think...

 

[Sturm Vogel]

The total force that acts on the wheel is:

0.92 N*m / 0.35 m = 2.6 N

The linear acceleration of the wheel is:

2.6 N / 0.90 kg = 2.9 m/s^2

The angular acceleration of the wheel is:

2.9 m/s^2 / 0.35 m = 8.3 rad/s^2