A Physics maximum height question?

E

Elizabeth

New member
An athlete in good physical condition can land on the ground at a speed of up to 12 m/s without injury. Calculate the maximum height from which the athlete can jump without injury. Assume the takeoff speed is zero,

---please... i need to know HOW to do it too... please be very specific.
 
h = -16t^2 + vt
h = height after thrown or dropped
v = initial velocity (ft per second)
t = time in motion
thats all that i can reamber
 
Ignoring air resistance...

Your three knowns:
initial velocity Vo = 0
final velocity V = -12m/s
acceleration a = -9.8m/s^2

Your unknown:
height = ?

Use the equation V^2 = Vo^2 + 2ay
solve for y, I get y = 7.4 meters
 
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