A easy physics question i dont get....??? plz help?

G

graphicer89

New member
ok 2 people reached the summit of mount everest and they climbed the last 400 METERS of the ascent in 4 HOURS(or about 14,400 seconds).Rounding to the nearest hundredth what was the AVERAGE SPEAD in meters per second of the last part of their climb? What formula can i use? and how would i come to the conclusion..?
 
you don't need a formula, you look at the data, meters and seconds, and you look at the requirement, meters per second, and you make the big jump to decide to divide the meters by the seconds to get meters per seconds.

400 m / 14400 sec = 0.0278 m/s, or rounded, 0.03 m/s

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kay. first, you can eliminate extra info which is the fact that there were two people. Lay out your givens:

distance = 400 metres
time = 4 hrs = 14 400 seconds
average speed = ???

The question fully says: what was the AVERAGE SPEAD in meters per second of the LAST PART of their climb?
meaning you aren't calculating their speed from rest, soo v initial and v final aren't necessary to consider. Because your distance of the LAST PART and the time it takes is given,

you would thus use v = d/t
simple.
 
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