D
dpet119
Guest
The specific heat of a substance is approximately 0.5 cal/g-°C. If 30 calories of heat are absorbed by 15 g of the substance at 30°C, it's temperature will become...
ok so i don't even know what to solve for: I'm guessing that:
Specific Heat=.5
Cal.=30
grams=15
DELTA=x
but what about the other variable? Please help
ok so i don't even know what to solve for: I'm guessing that:
Specific Heat=.5
Cal.=30
grams=15
DELTA=x
but what about the other variable? Please help