SIMPLE:
this is the conservation of heat problem and we know that heat is never lost in situation like this but is absorbed or exchanged by the objects. so the equation to solve this problem is:
Q=mc?T where Q is the Energy, m is the mass, c is the specific heat capacity and ?T is the change in temperature.
Data:
ice--> mass=.45kg, c=2090J/kgC, and ?T=0 degrees
Water--> mass=?, c=4186J/kgC, and ?T= -8 degrees Celsius
Our equation: mc?T+mc?T=0
(.45kg)(2090J/kgC)(0)+(m)(4186J/kgC)(-8)=0
940.5J/C-33488m=0
-33488m=-840.5J/C
m=.028kg or 28grams
so your answer is that there were 28grams of water in the sample.
