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T
P=P(i)*R^(t/period) P=Population, P(i)=initial Population, R=Rate of growth
(a) P=300*3^(t/3hours)
(b) P(4)=300*3^(4/3)=1298 bacteria
(c) 1910=300*3^(t/3hours) -- solve for t
191/30=3^(t/3hours)
log(191/30)/log(3)=t/3hours
1.684922=t/3hours
t=5.05477 hours
