Search results
-
T
A bacteria culture starts with 300 bacteria and grows at a rate propotional to its
P=P(i)*R^(t/period) P=Population, P(i)=initial Population, R=Rate of growth (a) P=300*3^(t/3hours) (b) P(4)=300*3^(4/3)=1298 bacteria (c) 1910=300*3^(t/3hours) -- solve for t 191/30=3^(t/3hours) log(191/30)/log(3)=t/3hours 1.684922=t/3hours t=5.05477 hours- Tomba
- Post #2
- Forum: Discuss Culture
-
T
A bacteria culture starts with 300 bacteria and grows at a rate propotional to its
P=P(i)*R^(t/period) P=Population, P(i)=initial Population, R=Rate of growth (a) P=300*3^(t/3hours) (b) P(4)=300*3^(4/3)=1298 bacteria (c) 1910=300*3^(t/3hours) -- solve for t 191/30=3^(t/3hours) log(191/30)/log(3)=t/3hours 1.684922=t/3hours t=5.05477 hours- Tomba
- Thread
- Replies: 2
- Forum: Discuss Culture