Atomic wqeights: Al=27, I=127, I2=254, AlI3=408
2Al + 3I2 ===> 2AlI3
A. 3.02gAl x 1molAl/27gAl = 0.112 mole Al
B. 15.1gI2 x 1molI2/254gI2 = 0.059 mole I2
From the balanced equation, 3 moles of I2 needs 2 moles Al. Or, 3/2 mole I2 needs 1 mole Al. So 0.112 mole Al needs (3/2)(0.112) = 0.168...