Recent content by Bandagadde S

a) By Gauss's theorem the flux through the closed surface = φ = q/εo = -3.6 x 10^-6/8.9 x 10^-12 = 4x10^5 N.m^2/C b) q = εo φ = 8.9x10^-12 x 780 = 0.00694 x10^-6 C = 0.007 μC c) The flux through the surface does not depend on the position of the charge within the surface. It depends on...

At the extreme position of the string when the velocity becomes zero and the student is momentarily at rest the forces acting on him are the tension in the string T , The component of his weight mgcos θ along the string and opposite to T The component perpendicular to the above, mgsin θ For...

At the extreme position of the string when the velocity becomes zero and the student is momentarily at rest the forces acting on him are the tension in the string T , The component of his weight mgcos θ along the string and opposite to T The component perpendicular to the above, mgsin θ For...

A load of 3000 N = 3000/g =306.12245kg The total mass M = 480 + 306.12245 = 786.12245 kg a) The tension in the cable = F = Mg In the other cases 'a' has to be added to g with proper sign b) F = M(g+a) , where a = 1.5m/s^2 c) F = M(g-a) d) F = M(g-a) e) F = M(g+a)

Earth has an atmosphere. We are moving in it . The air inside the car moves along with the car and the fly also moves with the same speed as the car in addition to its zigzag movements. I think the fly is "attached" to the air inside the car !! The same holds for the ball thrown up. It already...