K Katy Noe New member Jun 25, 2011 #1 3k^2-3k/2k-2 Can you help me in solving this problem i've been stuck on it now for at least thirty minutes and it is really bugging me! Please help. Thank you for your help!
3k^2-3k/2k-2 Can you help me in solving this problem i've been stuck on it now for at least thirty minutes and it is really bugging me! Please help. Thank you for your help!
K Kimberley New member Jun 26, 2011 #2 Factor both top and bottom: 3k(k-1) / 2 (k-1) , cross out the k-1's to get: 3k / 2, which is your answer.
Factor both top and bottom: 3k(k-1) / 2 (k-1) , cross out the k-1's to get: 3k / 2, which is your answer.
N Nicole Mikloiche New member Jun 26, 2011 #3 I'm assuming this is (3k^2 - 3k) / (2k - 2) 1. Factor out 3k from the numerator giving us: 3k(k - 1) / 2k - 2 2. Factor out 2 from the denominator giving us: 3k(k - 1) / 2(k - 1) 3. Reduce the expression by cancelling (k-1) from numerator and denominator 4. Answer: 3k/2
I'm assuming this is (3k^2 - 3k) / (2k - 2) 1. Factor out 3k from the numerator giving us: 3k(k - 1) / 2k - 2 2. Factor out 2 from the denominator giving us: 3k(k - 1) / 2(k - 1) 3. Reduce the expression by cancelling (k-1) from numerator and denominator 4. Answer: 3k/2
