L Lazy Eight (∞) New member Jul 7, 2009 #2 1. log_8(4) = 2/3 8^(2/3) = 4 2. log_5(125) = 3 5^(3) = 125
M MisterSams New member Jul 7, 2009 #3 1. 4 = 8^(2/3) 2. 125 = 5^(3) its just about moving the components of the log form into place for exponential form... not really much "math" required. so[ log (2) x = 3 ]----> X = 2^(3) its that simple.
1. 4 = 8^(2/3) 2. 125 = 5^(3) its just about moving the components of the log form into place for exponential form... not really much "math" required. so[ log (2) x = 3 ]----> X = 2^(3) its that simple.
