Wouldn't an intelligent being count in binary?

Jared

New member
but to count in binary you need to know the following:

1 + 1 = 10 (2)
1 + 0 = 1 (duh)
0 + 0 = 0 (duh)
1 * 1 = 1 (duh)
0 * 0 = 0 (duh)
1 * 0 = 0 (duh)
0 * 1 = 0 (duh)

To be able to perform general add algorithm, you need to know the following for decimal:

1 + 1 = 2
1 + 2 = 3
1 + 3 = 4
1 + 4 = 5
1 + 5 = 6
1 + 6 = 7
1 + 7 = 8
1 + 8 = 9
1 + 9 = 10
2 + 2 = 4
2 + 3 = 5
2 + 4 = 6
2 + 5 = 7
2 + 6 = 8
2 + 7 = 9
2 + 8 = 10
2 + 9 = 11
3 + 3 = 6
3 + 4 = 7
3 + 5 = 8
3 + 6 = 9
3 + 7 = 10
3 + 8 = 11
3 + 9 = 12
4 + 4 = 8
4 + 5 = 9
4 + 6 = 10
4 + 7 = 11
4 + 8 = 12
4 + 9 = 13
5 + 5 = 10
5 + 6 = 11
5 + 7 = 12
5 + 8 = 13
5 + 9 = 14
6 + 6 = 12
6 + 7 = 13
6 + 8 = 14
6 + 9 = 15
7 + 7 = 14
7 + 8 = 15
7 + 9 = 16
8 + 8 = 16
8 + 9 = 17
9 + 9 = 18

There are 45 combinations that you HAVE to memorize--or compute!!!

And thats just FOR adding, there's still the multiplication table...and this all assumes commutativity so that you don't have to write the reverse of each one (like I did for binary)
 
Back
Top