M missvictoria Guest Jan 22, 2009 #1 ...cyclist to bring a bicycle with? an initial speed of 6.5m/s to a complete stop? I'm new with physics does anyone know how I can set up this equation?
...cyclist to bring a bicycle with? an initial speed of 6.5m/s to a complete stop? I'm new with physics does anyone know how I can set up this equation?
F farwallronny Guest Jan 22, 2009 #2 5.417 seconds. 6.5 / 1.2 = 5.417 The bicycle will lose 1.2 m/s of it's velocity every second. The entire process will take 5.417 seconds.
5.417 seconds. 6.5 / 1.2 = 5.417 The bicycle will lose 1.2 m/s of it's velocity every second. The entire process will take 5.417 seconds.
F farwallronny Guest Jan 22, 2009 #3 5.417 seconds. 6.5 / 1.2 = 5.417 The bicycle will lose 1.2 m/s of it's velocity every second. The entire process will take 5.417 seconds.
5.417 seconds. 6.5 / 1.2 = 5.417 The bicycle will lose 1.2 m/s of it's velocity every second. The entire process will take 5.417 seconds.
D David Guest Jan 22, 2009 #5 acceleration = change in speed / time acceleration = (final speed - initial speed) / time a = (vf - vi)/t to solve for time, multiply both sides by t and divide by a: t = (vf - vi)/a now substitute values: t = (0 - 6.5)/(-1.2) t = 6.5/1.2 => t = 5.4 s <=
acceleration = change in speed / time acceleration = (final speed - initial speed) / time a = (vf - vi)/t to solve for time, multiply both sides by t and divide by a: t = (vf - vi)/a now substitute values: t = (0 - 6.5)/(-1.2) t = 6.5/1.2 => t = 5.4 s <=
