P
Pablo
Guest
C + D <---> CD
CD + D ----> CD_2 Slow step
CD_2 + D ----> CD_3
The answer is
k * [CD] * [D]
What i don't understand is why you don't sub in C + D <---> CD into the slow step (rate determining step).
So it comes out C + D + D ----> CD_2
I know you do this in some problems, try to sub in stuff, but what is different about this one that you don't do that procedure.
CD + D ----> CD_2 Slow step
CD_2 + D ----> CD_3
The answer is
k * [CD] * [D]
What i don't understand is why you don't sub in C + D <---> CD into the slow step (rate determining step).
So it comes out C + D + D ----> CD_2
I know you do this in some problems, try to sub in stuff, but what is different about this one that you don't do that procedure.