What is the displacement of a bicycle that travels 8.0 m/s [N] for 15s?

  • Thread starter Thread starter Kay E
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Kay E

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I know that displacement=average velocity/time, I just don't know how to put it all together... help!
 
Note that displacement is a vector quantity - it has magnitude and direction.

Distance is a scalar quantity - magnitude only.

So from you question (should use distance = initial velocity x time +1/2 accelerationxtime squared, but no accel, so just becomes velocity x time)

Distance = 8 x 15 = 120 metres

Displacement would be, for example, 120m North or 120 metres at a bearing of 0 degrees etc.
 
the formula is
d=vi*t+1/2at^2
now here the bicycle is travelling with uniform velocity so
accleration=a=0m/s^2
initial velocity=vi=8m/s
and
time=t=15s

putting values in formula
d=8x15+1/2x0x15^2
d=8x15
d=120 m
 
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