What is the direction of the car's acceleration at t=10 s?

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gbutterfly339

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A 1600 kg car starts from rest and drives around a flat 64-{\rm m}-diameter circular track. The forward force provided by the car's drive wheels is a constant 1300 N.

What is the direction of the car's acceleration at t=10 s? Give the direction as an angle from the r-axis. in degrees.

If the car has rubber tires and the track is concrete, at what time does the car begin to slide out of the circle?


I found the magnitude of the car's acceleration at t-10 to be 2.2 m/s^2.

I thought the answer for the direction was 87 or 12.7. I tried both but came up miserably wrong. Any help or advice?

I have no idea where to start to find the time the car slides off the track.
 
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