A 67.2 g sample of a gold and palladium alloy contains
2.49 E 23 atoms. What is the composition (by mass) of the
alloy?
This is what I have so far:
67.2 g alloy = mass of Au + mass of Pd
67.2 g alloy = 196.97*x + 106.42*y
where x & y are the moles of gold and palladium respectively.
Total moles of alloy is 2.49 E 23 atoms * (1 / 6.022 E 23) = 0.413 moles of alloy.
There is no reason to think that x & y are the same. In fact, if you assume that you get the wrong answer.
which was 43.6g Au and 23.6g Pd. This has Au at approx. 65%. The answer in the back of the book is 75.0%. Any help appreciated.
2.49 E 23 atoms. What is the composition (by mass) of the
alloy?
This is what I have so far:
67.2 g alloy = mass of Au + mass of Pd
67.2 g alloy = 196.97*x + 106.42*y
where x & y are the moles of gold and palladium respectively.
Total moles of alloy is 2.49 E 23 atoms * (1 / 6.022 E 23) = 0.413 moles of alloy.
There is no reason to think that x & y are the same. In fact, if you assume that you get the wrong answer.
which was 43.6g Au and 23.6g Pd. This has Au at approx. 65%. The answer in the back of the book is 75.0%. Any help appreciated.