A car travels 2.83 km in the x-direction, then turns left 65.3◦ to the original direction and travels an additional distance of 3.38 km. Calculate the x component of the car’s net displacement.
Let : d1 = 2.83 km,
theta = 65.3◦ , and
d2 = 3.38 km.
Note: we aren't allowed to solve with law of sines or law of cosines. please teach me another way!
Let : d1 = 2.83 km,
theta = 65.3◦ , and
d2 = 3.38 km.
Note: we aren't allowed to solve with law of sines or law of cosines. please teach me another way!