the rate law is therefore?

heather

New member
For the reaction, A + 2 B  C + 2 D, some measurements of the initial rate of reaction at vary¬ing concentration gave the following data.

Experiment [A] Rate (mol L 1 s 1 )
1 0.100 0.200 0.000360
2 0.150 0.200 0.000540
3 0.150 0.250 0.001055

a.the rate law is therefore: rate = k[A]2
b.the rate law is therefore: rate = k[A]2
c.the rate law is therefore: rate = k[A]22
d.the rate law is therefore: rate = k[A]
e.the rate law is therefore: rate = k[A]3
 
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