The probability of a teenager owning a CD player is 0.45, of owning a bicycle is 0.36...

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Omy

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...& of owning both is 0.27? If a teenager is selected at random, find the probability that he or she owns a CD player or a bicycle.
 
P(A or B) = P(A) + P(B) - P(A and B)

Here, we have P(A) = 0.45, P(B) = 0.36, P(A and B) = 0.27

P(A or B) = 0.45 + .36 - .27

P(A or B) = 0.81 - .27 = .54
 
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