The perimeter of a rectangle garden is 110 feet. What is its dimensions if the

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Gabi

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length is 5 less than twice the?
and how do you get it?
im sorry the end of the question is "5 less than twice the width"
 
Let the width be x

The length is (2x - 5)

The perimeter = x + (2x - 5) + x + (2x - 5)

= 6x - 10, so

6x - 10 = 110, so

6x = 120, so

x = 20, and length = 2 x 20 - 5 = 40 -5 = 35.
 
...you need to finish the question... 2l+2w=P
based on the information given... l=2w-5
now the equation is 2(2w-5)+2w=P
P=110
so plug in and solve 2(2w-5)+2w=110
4w-10+2w=110
6w-10=110
6w=120
w=20
now that we know what w equals we can plug that into the original equation 2l+2w=110
2l+2(20)=110
2l=70
l=35
therefore the width is 20 and the length is 35
which fits the criteria of the question. 35m is 5 less than twice the length.
 
Perimeter = length + width + length + width
110 = x + (2x-5) + x + (2x-5)
110 = 6x - 10
120 = 6x
20 = x
Length = 35 feet
Width = 20 feet
 
not enough information, twice the what?
Let's assume you mean width.
length then is (2x - 5)
width is x so you have
2(2x - 5) + 2x = 110 then
4x - 10 + 2x =110 then
6x = 120 then
x = 20
so
width is 20 , length is 35
20 + 35 +20 + 35 = 110
 
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