R Rayne Bow New member Oct 26, 2010 #1 The net force acting on 12.6kg object is given by Fx=(20-x) N, where Fx is in the newtons and x is in the meters. How much work is done on the object as it moves from x=0 to x=10m? Answer is: 150 J Please help!
The net force acting on 12.6kg object is given by Fx=(20-x) N, where Fx is in the newtons and x is in the meters. How much work is done on the object as it moves from x=0 to x=10m? Answer is: 150 J Please help!
