Solving Pre-calc equation. Please help!!?

[santmann2002]

tan2x=1 so 2x = pi/4+kpi and x= pi/8+kpi/2
solutions
x=pi/8,5pi/8,9pi/8 ,13pi/8

 

[John]

Solve equation on the interval [0,2?).

3tan(2x) - 1 = 4tan(2x) - 2