E Evan W New member Feb 21, 2011 #1 (x+1)(dy/dx)=2xy-3xy^2, y(0)=-1 The equation appears to be separable to dy/(2y-3y^2)=(x/(x+1))dx Integrating, I get 1/2(ln-ln(2-3y))=x-ln(x+1)+C However, when I try to solve for C I get a non-real answer. Am I doing something wrong?
(x+1)(dy/dx)=2xy-3xy^2, y(0)=-1 The equation appears to be separable to dy/(2y-3y^2)=(x/(x+1))dx Integrating, I get 1/2(ln-ln(2-3y))=x-ln(x+1)+C However, when I try to solve for C I get a non-real answer. Am I doing something wrong?
-ln(2-3y))=x-ln(x+1)+C