L Lola New member Sep 16, 2010 #1 How do I solve: y"=ky' y"-ky'=o where p(x)=k and r(x)=o I know that I need to find y1, but I have tried guessing and nothing works. Once I find y1, then I can use this formula: U=1/(y1)^2 * e^(integral pdx) where p(x)=k (from original equation)
How do I solve: y"=ky' y"-ky'=o where p(x)=k and r(x)=o I know that I need to find y1, but I have tried guessing and nothing works. Once I find y1, then I can use this formula: U=1/(y1)^2 * e^(integral pdx) where p(x)=k (from original equation)
