A ladder 10 m long rests against a vertical wall wall. If the bottom of the ladder slides away from the wall at a speed of 2 m/s, how fast is the angle between the top of the ladder and the wall changing when the angle is 45 degrees?
The book tells me the answer is 2/ squareroot 5.
This is what I have so far:
x=10sin(a)
y=10cos(a)
And I need to somehow use that information with 2x(dx/dt) + 2y(dy/dt) = 0
Please use this method!!
The book tells me the answer is 2/ squareroot 5.
This is what I have so far:
x=10sin(a)
y=10cos(a)
And I need to somehow use that information with 2x(dx/dt) + 2y(dy/dt) = 0
Please use this method!!