prove A and At (traspose) have the same characteristic polynomial?

chicago chicago

New member
For matrix A
Use properties of Determinants to prove A^t and A have same characteristic transpose.
n=>lambda=>eigen value (I dont know how to write lambda here)

I know characteristic matrix if found from Det(A-nI) and Det(A) = Det(At)

so I have writen down:
Det(A-nI) = Det(At-nI) = 0
but i am not sure where to go from here....
help would very much be appreciated.
 
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